p(1+q^2)=q(z-a)

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Solution for p(1+q^2)=q(z-a) equation:


Simplifying
p(1 + q2) = q(z + -1a)
(1 * p + q2 * p) = q(z + -1a)
(1p + pq2) = q(z + -1a)

Reorder the terms:
1p + pq2 = q(-1a + z)
1p + pq2 = (-1a * q + z * q)
1p + pq2 = (-1aq + qz)

Solving
1p + pq2 = -1aq + qz

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Reorder the terms:
aq + 1p + pq2 + -1qz = -1aq + qz + aq + -1qz

Reorder the terms:
aq + 1p + pq2 + -1qz = -1aq + aq + qz + -1qz

Combine like terms: -1aq + aq = 0
aq + 1p + pq2 + -1qz = 0 + qz + -1qz
aq + 1p + pq2 + -1qz = qz + -1qz

Combine like terms: qz + -1qz = 0
aq + 1p + pq2 + -1qz = 0

The solution to this equation could not be determined.

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